Chemistry, 14.10.2019 18:00 harringtonrob16

Insoluble sulfide compounds are generally black in color.
which of the following combinations could yield a black precipitate?
na2s(aq)+kcl(aq)
li2s(aq)+pb(no3)2(aq)
pb(clo3)2(aq)+nano3(aq)
agno3(aq)+kcl(aq)
k2s(aq)+sn(no3)4(aq

Answers: 3

Show answers

Answers

A black precipitate is formed by the reaction; Li2S(aq) + Pb(NO3)2(aq) > PbS(s) + 2LiNO3(aq) and K2S(aq) + Sn(NO₃)₄(aq)→ SnS(s) + KNO₃(aq)

A double decomposition reaction is a type of reaction in which the cations exchange anion partners in the product. Sometimes, a double decomposition reaction yields a precipitate. A precipitate is a solid product of the reaction between two aqueous species.

Given the options in the question, a black precipitate is formed by the reaction; Li2S(aq) + Pb(NO3)2(aq) > PbS(s) + 2LiNO3(aq) and K2S(aq) + Sn(NO₃)₄(aq)→ SnS(s) + KNO₃(aq)

Learn more: link

Answer from: djdkfkfkckmfmf9919

Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)

K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

Explanation:According to solubility rules, metal sulfides are insoluble except Calcium sulfide(CaS), Magnesium sulfide(MgS), Barium sulfide(BaS), and those of potassium, sodium, and ammonium.Therefore, when all the other sulfides are formed during a reaction they form a precipitate that is shown to be in solid-state.Precipitates are formed during precipitation reactions when cations and anions combine to form a compound that is insoluble in water.

In our case; In the equations given, some reactions will take place to form a precipitate while others will not occur.

That is;

Na₂S(aq)+KCl(aq) → No reaction Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)Pb(ClO₃)₂(aq)+NaNO₃(aq) → No reaction AgNO₃(aq)+KCl(aq) →AgCl(s) + KNO₃(aq)K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

The first reaction will not occur.

The second equation is a precipitation reaction that forms lead(ii)sulfide which is a black precipitate.

The third reaction will not take place.

The fourth reaction will be a precipitation reaction forming silver chloride precipitate.

The fifth equation is also a precipitation reaction that forms tin(ii) sulfide, SnS which is a black precipitate.

Therefore; the equations that answers our question are;

Li₂S(aq)+Pb(NO₃)₂(aq) → PbS(s) + LiNO₃(aq)K2S(aq)+Sn(NO₃)₄(aq→ SnS(s) + KNO₃(aq)

Answer from: Quest

put the answers and i could answer.

Answer from: Quest

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

Another question on Chemistry

Chemistry, 21.06.2019 20:20

Calculate the molarity of the solution. 6.02 x 1022 molecules of hci (molecular weight = 36.5 g/mole) in 2.0 liters of water m

Answers: 1

Answer

Chemistry, 22.06.2019 01:40

C3h8o3 - glycerol major species present when dissolved in water

Answers: 2

Answer

Chemistry, 22.06.2019 07:20

After watching the video "zinc strip in copper nitrate solution", and reading the instructions, click on the link labeled "start" just below the drawing of the pencil tip. follow the direction to complete the 3x3 grid. answer the below questions for the portion of the activity in which sn(s) is placed in agno3(aq)

Answers: 1

Answer

Chemistry, 22.06.2019 11:40

Modern pennies are composed of zinc coated with copper. a student determines the mass of a penny to be 2.482 g and then makes several scratches in the copper coaling (to expose the underlying zinc). the student puts the scratched penny in hydrochloric acid, where the following reaction occurs between the zinc and the hcl (the copper remains undissolved): zn(s) + 2 hcl(aq) → h2(g) + zncl(aq)the student collects the hydrogen produced over water at 25 °c. the collected gas occupies a volume of 0.899 l at a total pressure of 79 j mmhg. calculate the percent zinc (by mass) in the penny. (assume that all the zn in the penny dissolves.)

Answers: 1

Answer

You know the right answer?

Insoluble sulfide compounds are generally black in color.
which of the following combinations...

Questions