Assume an object a mass of 36.240 g and it’s density is 5.40 g/ml. what is it’s volume

The volume of the object=6.71ml

Given:

Mass of the object=36.240g

Density of the object=5.40

To find:

Volume of the object

Step by Step Explanation:

Solution:

According to the formula, Density of the object is given as

and from this volume can be derived as

Where, m=mass of the cylinder

=density of the cylinder

v=volume of the cylinder

We know the values of m=36.240g and =5.40

Substitute these values in the above equation we get

v=36.240/5.40

=6.71ml

Result:

Thus the volume of the object is 6.71ml

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.