Ahygroscopic compound readily absorbs water from the air. this water can be removed by gently heating the compound. 5.24 g of a hygroscopic compound was heated to remove the absorbed water. after heating the dry compound had a mass of 4.16 g. what was the mass percent of water in the original compound?

This means 20.6% of the original hygrocopic compound is water

Explanation:

Step 1: Given data

A hygroscopic compound weighs 5.24 grams

To remove the absorbed water the compound is heated.

After the heating process, the compound weighs 4.16 grams

Step 2: Calculate the mass of the water

The total mass of the hygroscopic compound = mass of water + mass of dry compound

The mass of water = The total mass of the hygroscopic compound - mass of dry compound

The mass of water = 5.24 grams - 4.16 grams = 1.08 grams

Step 3: Calculate the mass percent of water in the original compound

1.08g / 5.24g *100% = 20.6%

Step 4: To control this we can calculate the mass percent of the dry compound

4.16g / 5.24g *100 % = 79.4%

20.6% + 79.4% = 100%

This means 20.6% of the original hygrocopic compound is water

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

bcde is the incorrect answer it is a