The decomposition reaction: so, cl, so2 + cl2, has a first order rate constant of 2.2 x 10's at 320 °c. if the initial concentration of so2cl2 is 0.0040 m, what will be its concentration be (a) after 1.00 hr and (b) after 1.00 day?

Answer :

(a) The concentration of after 1.00 hr will be 0.0037 M

(b) The concentration of after 1.00 day will be 0.00060 M

Explanation :

(a) The expression for first order reaction is:

where,

= concentration of at time 't'  = ?

= concentration of at time '0' = 0.0040 M

k = rate constant = (assuming the power of 10 from the correct source)

t = time = 1.00 hr = 3600 s (1 hr = 3600 s)

Now put all the given values in the above expression, we get:

Thus, the concentration of after 1.00 hr will be 0.0037 M

(b) The expression for first order reaction is:

where,

= concentration of at time 't'  = ?

= concentration of at time '0' = 0.0040 M

k = rate constant =

t = time = 1.00 day = 86400 s (1 day = 86400 s)

Now put all the given values in the above expression, we get:

Thus, the concentration of after 1.00 day will be 0.00060 M

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: