Calculate the standard enthalpy of the 3rd reaction using the given data: h2(g) +126) +2 hio) a, hº = +52.96 kj/mol 2 h2(g) + o2(g) + 2 h209) a, hº = - 483.64 kj/mol 4 hi) + o2(g) +2 12(8) + 2 h206) a, hº =? a. h=-589.5619/mol calculate the internal energy change for reaction (3) in the previous problem.

The standard enthalpy of the 3rd reaction is -586.56 kJ/mol.

Explanation:

...[1]

...[2]

..[3]

By using Hess's we can determine the standard enthalpy of reaction of third reaction:

[2] - 2 × [1] = [3] (Hess's law)

The negative sign indicates that energy is released during this reaction.

The standard enthalpy of the 3rd reaction is -586.56 kJ/mol.

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