What is the pressure of 0.38 mol of gas if it has a volume of 9.614 l and a temperature of 255 k. the gas constant is i (hint: don't worry about what a "pas constant" is just make the units work! this is a conversion factor do not plug any numbers into it. use it to cancel units) ball park 0.8-0.9 atm

The answer to your question is: P = 0.827 atm

Explanation:

Data

n = 0.38 mol

volume = 9,614 l

temperature = 255 °K

R = 0.08206 atm L/mol°K

Formula

              PV = nRT

             P = nRT / V

Process

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j