How many grams of lead (ll) chloride are produced from the reaction of 25g of sodium chloride according to the balanced reaction? pb(no3)2 + 2 nacl = pbcl2 + nano3

The answer to your question is:  25 g of PbCl2

Explanation:

Data

NaCl = 25 g

PbCl₂ = ?

                       Pb(NO3)2 + 2 NaCl ⇒ PbCl2 + NaNO3

MW NaCl = 58.5 g

MW PbCl2 = 277 g

                       2(58.5 g) of NaCl  277 g of PbCl2

                       25 g  of NaCl           x

                       x = (25 x 277) / 117

                       x = 25 g

4d^55s^1 ( third choice)