The latent heat of vaporization of ethanol is 200 calories/gram. this means that about 200 calories of heat must be added to 1 gram of ethanol to change its temperature about 200 calories of heat must be added to 1 gram of ethanol to convert it from a solid to a liquid about 200 calories of heat must be added to 1 gram of ethanol to convert it from a liquid to a gas

Heat of vaporization refers to the amount of energy required to vaporize some amount of a substance depending on the units.  Since the units in this case is calories/gram, 200 calories are required to vaporize 1 gram of ethanol.  This means that it takes 200 calories to convert 1 gram of ethanol from a liquid to a gas.

I hope this helps.  Let me know if anything is unclear.

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.

                             

Sorry i dont understand the question can you rephase it?