Calculate the ph of a 0.50 m hio. the ka of hypoiodic acid, hio, is 2.3x10–11.0.305.325.479.474.80

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = = 2.3 * 10⁻¹¹

At equilibrium:

Replacing those values in the equation for Ka and solving for x:

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

a. they are both space stations

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the answer is definitely c.