How many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? (1 electrons, 2 electrons, 3 electrons, 4 electrons. licl, naf, cao, bas, nabr)

The answer to your question is:

Explanation:

Compound                 Cation                 Anion         Number of electrons

LiCl                              Li⁺¹                        Cl⁻¹                  one

NaF                             Na⁺¹                       F⁻¹                    one

CaO                            Ca⁺²                       O⁻²                  two

BaS                             Ba⁺²                        S⁻²                  two

NaBr                           Na⁺¹                       Br⁻¹                   one

Explanation:

To understand how the answer is gotten, it is recommended to prepare the ionic equation for watch of the compounds and this can be gotten by considering the valency of the atoms.

LiCl;

Li belongs to group 1 so it has a valency of + 1

Cl belongs to group 7 so it has a valency of -1

Ionic equation is given as; Li+ + Cl- -> LiCl

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.

NaF;

Na belongs to group 1 so it has a valency of + 1

F belongs to group 7 so it has a valency of -1

Ionic equation is given as; Na+ + F-   ->  NaF

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.

CaO;

Ca belongs to group 1 so it has a valency of + 2

Cl belongs to group 6 so it has a valency of -2

Ionic equation is given as; Ca2+  + O2-  -> CaO

The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.

BaS;

Ba belongs to group 2 so it has a valency of +2

S belongs to group 6 so it has a valency of -2

Ionic equation is given as; Ba2+ + S2-   ->  BaS

The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.

NaBr;

Na belongs to group 1 so it has a valency of + 1

Br belongs to group 7 so it has a valency of -1

Ionic equation is given as; Na+ + Br- -> NaBr

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.