Zinc fluoride (znf2) dissociates according to the following equation: znf2(s) ⇌ zn2+(aq) + 2f–(aq) ksp of this equilibrium is 3.0 × 10–2. if the concentration of zinc ions (zn2+) in a solution is measured to be 4.4 × 10–1 m, what is the concentration of the fluoride ions (f–)?

[F⁻]² = 0.068 M

Explanation:

ZnF₂(s) ⇌ Zn²⁺(aq) + 2F⁻(aq)

At equilibrium the Kps can be calculated by the following equation:

Kps = [Zn²⁺][F⁻]²

Therefore, the concentration of F⁻¹ can be calculated:

[F⁻]² = Kps/ [Zn²⁺]

[F⁻]² = = 3.0 x 10⁻² / 4.4 x 10⁻¹M

[F⁻]² = 0.068 M

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explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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explanation: