When 50. ml of 10% (m/v) nacl is diluted to 500. ml the nacl concentration is %

= 0.01 % m/v

From the information given we first need to understand the meaning of;

10% m/v, it means 10% mass to volume ratio

That is; 10g of a solute (NaCl) are present in 100 mL of solution (water)

Therefore;

First, we can determine the concentration of the initial solution of NaCl

Concentration = Moles ÷ Volume

But, Moles = Mass ÷ Molar mass

Molar mass of NaCl = 58.44 g/mol

Moles = 10 g ÷ 58.44 g/mol

         = 0.171 moles

Thus;

Concentration= 0.171 moles × 0.1 L

                       = 0.0171 M

Second, we can determine the concentration of the solution after dilution.

Using dilution equation;

M1V1 = M2V2

M2 = M1V1 ÷ V2

     = (0.0171 M×0.05 L) ÷ 0.5 L

     = 0.00171 M

Therefore, the concentration after dilution is 0.00171 M

Thirdly, we find the % by mass to volume ratio

Concentration = 0.00171 M ( means 0.00171 moles/liter)

Mass of NaCl = 0.00171 moles × 58.44 g/mol

                             = 0.09993

                             = 0.1 g

0.1 g = 1000 mL(1 L) (0.1 g/L)

To get % m/v we find the Mass in 100 mL will be;

= (0.1 g× 100 mL)÷ 1000 mL

= 0.01 % m/v

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

i think it's c. i'm not sure but i think so.