Asample of solid ammonium chloride was placed in an evacuated chamber, and then heated causing it to decompose according to the following reaction: nh4cl(s) nh3(g) + hcl(g) in a particular experiment the pressure of nh3(g) in the container was found to be 2.2 atm. calculate the value of kp for the decomposition of nh4cl(s) at this temperature. kp = submitshow hints

Kp = 4.84

Explanation:

Considering the ICE table for the equilibrium as:

                     NH₄Cl (s)      ⇔         NH₃ (g) +      HCl (g)

t = o              

t = eq                                                 x                      x

--------------------------------------------- --------------------------

Moles at eq:                                      x                      x

Given the pressure of NH₃ at equilibrium = 2.2 atm

x = 2.2 atm

The expression for the equilibrium constant is:

So,

x = 2.2 atm

Thus,  

Thus, Kp = 4.84

i think its 5049.

i hope this !