Oxygen gas can be generated by heating kclo3 in the presence of some mno2. 2kclo3 → 2kcl + 3o2 if all the kclo3 in a mixture containing 2.24 g kclo3 and 0.30 g mno2 is decomposed, how many liters of o2 gas will be generated at t = 22.0°c and p = 762.7 torr?

0.249 L O2 gas

Explanation:

This a limit reagent problem, which means that you have to calcule how much product will form supposing a complete chemical reaction upon a limit of one reagent (the one you have the less quantity stoichiometrically).

To calcule the limit reagent you need to do your calculations in moles since a chemical reaction is expressed in moles of any given compound, so you calcule how many moles are in certain grams of MnO2 or KClO3 using their molecular weight. Also you divide the number of moles by the stoichiometric coefficient (given by the reaction) because you need to take into account how many moles of the compound are necessary for the reaction to continue.

Knowing the moles formed you can use the ideal gas law to calcule the volume of O2 in the given conditions: