Acylinder with a moveable piston contains 92g of nitrogen. the external pressure is constant at 1.00 atm. the initial temperature is 200k. when the temperature is decreased by 64 k, by putting it in a lower temperature freezer, the volume will decrease, according to the ideal gas law. calculate the work for this process. express your answer in j. the conversion factor between liter atmospheres and joules is 101.3 j = 1 l atm. the gas constant is 0.08206 (l atm)/(mol k). molecular weight of nitrogen is 28 g/mol

The work for this process is 3715J

Explanation:

The work done by a gas in an isobaric process is:

W = -P ΔV

By ideal gas law:

PΔV = nRΔT

Thus:

W = -nRΔT

Where n are moles of nitrogen:

92g × (1mol / 28g) = 3,286 moles

R is gas constant (0,08206atmL/molK)

And ΔT is the temperature changing (64K - 200K = -136K)

Replacing, work is:

w = 36,7 atmL. In joules:

36,7 atmL × (101,3J / 1atmL) = 3715J

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