The levels of mercury in two different bodies of water are rising. in one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. in the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year. which equation can be used to find y, the year in which both bodies of water have the same amount of mercury? a. 0.05 – 0.1y = 0.12 – 0.06y b. 0.05y + 0.1 = 0.12y + 0.06 c. 0.05 + 0.1y = 0.12 + 0.06y d. 0.05y – 0.1 = 0.12y – 0.06

The correct answer is option c.

Explanation:

In body-1

Amount of Mercury level after y years = m

In body-2

Amount of Mercury level after y years = m'

The year in which both bodies of water have the same amount of mercury, the expression will be given ,m = m'

0.05 +0.1y = 0.12 + 0.06y

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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