Apiece of wood that measures 3.0 cm by 6.0 cm has a mass of 80.0 grams. what is the density of the wood. would it float?

1.111 g/cm³- Will not float

Explanation:

But; Volume = length × width × height

Volume of the wood = 3.0 cm × 4.0 cm × 6.0 cm

                                  = 72 cm³

Therefore;

Density = 80.0 g ÷ 72 cm³

           = 1.111 g/cm³

The density of the piece of the wood is 1.111 g/cm³ and will therefore, will NOT float  since it has a higher density than water.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2