Asample of gas contains 0.1900 mol of co(g) and 0.1900 mol of no(g) and occupies a volume of 22.0 l. the following reaction takes place: 2co(g) + 2no(g)2co2(g) + n2(g) calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant.

V₂ = 16.5 L

Explanation:

To solve this problem we use Avogadro's law, which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

We use the reaction to calculate n₂:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

0.1900 mol CO * 0.1900 mol CO₂

0.1900 mol NO * 0.095 mol N₂

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml