If 30.0 g absorbs 255 j of heat, how much does the temperature of the water change? would the temperature be increasing or decreasing?

Change in temperature = 2.03°C, the temperature is increasing

In this case;

Mass of water = 30.0 g

Quantity of heat absorbed = 255 J

Specific heat capacity of water = 4.186 J/g°C

Rearranging the formula, Δt = Q ÷ mc

Δt = 255 J ÷ (4.186 J/g°C×30.0 g )

  = 2.03 °C

The temperature change is 2.03°C, the temperature is therefore increasing.

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.