Chemistry, 25.10.2019 20:43 babycakez143

What mass of pcl5 will be produced from the given masses of both reactants? 28.0 g of p4 and 59.0 g of cl2

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We have that from the Question, it can be said that mass of PCl5 will be produced from the given masses of both reactants

$Mass\ a\ PCl_5 =69g$

From the Question we are told

What mass of PCl_5 will be produced from the given masses of both reactants? 28.0 g of P4 and 59.0 g of Cl2

Generally the equation for reaction is mathematically given as

P_4+10Cl_2------4PCl_5

Therefore

No of moles P_4= $\frac{28}{124}$

No of moles P_4=0.225moles

No of moles of Cl_2= $\frac{59}{71}$

No of moles of Cl_2=0.831 moles

0.831 mole of Cl_2=0.0.831 moles of P4 and produce 0.3324 moles PCl_5

Therefore

$Mass\ a\ PCl_5 =moles\ of\ PCl_5 *molar\ mass\ PCl_5\\\\Mass\ a\ PCl_5 =0.3324+208$

Mass a PCl_5 =69g

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Answer from: janreyes39

PCl₅ mass = 69.3054 g

Further explanation

The reaction equation is the chemical formula of reactants and products

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reactants and products

Reaction

P₄ + 10 Cl₂ → 4 PCl₅

We look for moles of each reactant so we can determine the limiting of the reactants

mole P₄

mass 28.0 g

molar mass: 123.9

mole = mass : molar mass

mole = 28 : 123.9

mole: 0.2260

mole Cl₂

mass 59 g

molar mass: 71

mole = mass : molar mass

mole = 59 : 71

mole: 0.8310

From the coefficient of the equation above, it shows that the ratio of mol P₄: mol Cl₂ = 1:10

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

ratio P₄: 0.2260: 1 = 0.2260

ratio Cl₂: 0.8310: 10 = 0.08310

Because Cl₂ ratio smaller then Cl₂ becomes the limiting reactants

So mole PCl₅ is based on mole Cl₂

From the coefficient of reaction: mol PCl₅: mol Cl₂ = 4: 10

then mole PCl₅ = 4/10 x 0.8310 = 0.3324

molar mass PCl₅= 208.5

mass PCl₅ = mole x molar mass

PCl₅ mass = 0.3324 x 208.5

PCl₅ mass = 69.3054 g

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What mass of pcl5 will be produced from the given masses of both reactants? 28.0 g of p4 and 59.0 g...

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