Astudent used 0.29 g of a sample and added to it 50.0 ml of 0.100 m hcl. the resulting solution then required 39.50 ml of 0.0980 m naoh to reach a ph of 3.0. what is the acid consuming capacity of the sample in moles of acid neutralized per gram of sample?

Explanation:

The first step is to calculate the total amount of moles of HCl, so:

Then we can calculate the moles of HCl consumed in the reaction of NaOH:

Then we have to substract from the intial value to obtain the moles of HCl that react with the sample:

Finally to know the ratio between grams and moles we have to divide: