Calculate the amount of heat needed to raise 190.0 g of water vapor at 118 c to 150. c

12,281.6 Joules

In our case;

Mass of water vapor, m = 190.0 g

Change in temperature, Δt = 150°C - 118°C = 32°C

Taking the specific heat capacity of water vapor = 2.02 J/g°C

Therefore;

Amount of heat = 190.0 g × 2.02 J/g°C × 32°C

                          = 12,281.6 Joules

Hence, the amount of heat needed is 12,281.6 Joules

1 a

2 d

3 a

4 c

explanation: