Eugenol, the active ingredient of cloves, has a formula of c10h12o2. what is the boiling point of a solution containing 0.144 g of this compound dissolved in 10.0 g. of benzene? the kb for benzene is 2.53 oc/m, and its normal boiling point is 80.10 oc.

80.32 °C

Explanation:

The difference in the boiling point is

ΔT= Kb * m

m stands for molality, moles of solute (in this case eugenol) divided by kg of solvent (in this case benzene).

We're given Kb already, so in order to calculate ΔT we calculate m first:

m = 8.78 *10⁻⁴ mol / 0.01 kg = 0.0878 m

Finally we calculate ΔT:

ΔT = 2.53 °C/m * 0.0878 m = 0.22 °C

Thus the boiling point of the solution is

T₂ = T₁ + ΔT

T₂ = 80.10°C + 0.22°C

T₂ = 80.32 °C