What is the mass in grams of kbr in 0.400 l of a 0.350 m

The answer to your question is: 16.7 g of KBr

Explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

          = 0.14

MW KBr = 39 + 80 = 119 g

                                  119 g of KBr  1 mol

                                   x                   0.14 mol

                                   x = (0.14 x 119) / 1

                                   x = 16.7 g of KBr

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