Using the chemical equation in question 1 above, if 42.6 g of h2 reacts in excess nitrogen gas and the actual yield of nh3 was 200 g, calculate the percent yield of the reaction. hint: you'll need to calculate the theoretical yield, in g, of nh3 first.

The answer to your question is:  82.9 %

Explanation:

Data

H2 = 42.6 g

NH3 = 200 g

percent yield = ?

Reaction

                  3H2   +   N2   ⇒       2NH3

Process

                 6 g of H   34 g of N

                42.6 g          x

                 x = 241.4 g of NH3

percent yield = 200 / 241.4 x 100

                     = 82.9 %          

m=9

step-by-step explanation: