The xenon gas inside a car headlight bulb has a pressure of 2.00 atm at a temperature of 300 k. if the temperature of the gas rises to 1200 k when the headlights are switched on, what will be the new pressure in the bulb

P₂ = 8 atm

Explanation:

According to the Gay Lussac's law,

The pressure of given amount of gas is directly proportional to the its kelvin temperature at constant volume.

P ∝ T

P = K T

P/T = K    

P₁/T₁ = P₂/T₂

Given data:

Initial pressure = 2.00 atm

Initial temperature = 300 K

Final temperature = 1200 K

Final pressure = ?

Solution:

Formula:

P₁/T₁ = P₂/T₂

P₂ = P₁×T₂/T₁

P₂ = 2.0 atm ×1200 K / 300 K

P₂ = 2400 atm/ 300

P₂ = 8 atm

distance, luminosity, brightness, radius, chemical composition, and temperature

just did the assignment and the answer was #1 +2 n