If 192 grams of sulfur dioxide are reacted completely, determine both the number of moles and of sulfur dioxide reacted (the formula mass for sulfur dioxide is 64g/mol) and the number of miles of sulfur trioxide produced

3 moles SO₂ and 3 moles SO₃

We are given;

Mass of sulfur dioxide is 192 grams

Molar mass of sulfur dioxide is 64 g/mol

We are required to determine number of moles of sulfur dioxide and those of sulfur trioxide produced.

The equation for the reaction is, 2SO₂(g) + O₂(g) → 2SO₃(g)

Moles of a compound = Mass of a compound  ÷ Molar mass of the compound

Moles of SO₂ = 192 grams ÷ 64 g/mol

                      = 3 moles

Therefore, moles of sulfur dioxide that reacted are 3 moles

From the equation, two moles of SO₂ reacts to produce two moles of SO₃

Therefore, the mole ratio of SO₂ to SO₃ is 1:1

Thus; number of moles of SO₃ will be equal to the number of moles of SO₂

Hence, Moles of SO₃ = 3 moles

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the answer is either b or c