You are sitting in a cart at the top of hill on a roller coaster. you have 10500 j of gpe. if your current weight is 539 n, how tall is the hill you are sitting on?

h = 19.5 m

Explanation:

Given data:

GPE = 10500 J

weight = 539 N

height = ?

Solution:

One newton = 0.101971621 Kg

539 N = 54.963 Kg

GPE = mgh

h = GPE / mg

h = 10500 Kg m². s⁻² /  54.963 Kg × 9.8 m/s²

h = 10500 m / 538.64

h = 19.5 m

im not exactly sure but i think its b!

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)