According to the following reaction, how many grams of silver chloride will be formed upon the complete reaction of 30.1 grams of silver nitrate with excess sodium chloride? sodium chloride (aq) + silver nitrate (aq) silver chloride (s) + sodium nitrate (aq)

25.40 grams  Silver Chloride

Explanation:

We will sove this problem by using the stoichiometry based on the balanced equation of the reaction

AgNO3 + NaCl AgCl + NaNo3

we are given the amount in grams of silver nitrate so convert it to mol and then calculate mol silver chloride produced and convert this quantiy  to grams which is what is asked.

MW AgNO3 : 169.87 g/mol

MW AgCl: 143.32 g/mol

mol AgNO3 : 30.1 g / 169.37 g/mo = 0.18 mol AgNO3

0.18 mol AgNO3 x 1 mol AgCl/moll AgNO3 = 0.18 mol AgCl

0.18 mol AgCL x 143.32 g / mol AgCl = 25.40 g AgCl