4.) a in an experiment, 1.056 g of a metal carbonate,
containing an unknown metal m, is heated to give the
metal oxide and 0.376 g co2.
mco3(s) + heat → mo(s) + co2(g)
what is the identity of the metal m?
(a) m = ni
(c) m = zn
(b) m = cu
(d) m = ba
1

M= Cu

From the question;

Mass of metal carbonate = 1.056 g

Mass of CO₂ = 0.376 g

We are required to identify the metal M in the carbonate

The equation for the combustion of the carbonate;

MCO₃(s) + heat → MO(s) + CO₂(g)

Moles = Mass ÷ molar mass

Molar mass CO₂ = 44.01 g/mol

Moles = 0.376 g ÷ 44.01 g/mol

          = 0.00854 Moles

From the equation;

1 mole of the metal carbonate decomposes to yield 1 mole CO₂

Therefore; Mole ratio of MCO₃ : CO₂ = 1 : 1

Hence; Moles of MCO₃ = 0.00854 moles

Moles of MCO₃ = 0.00854 moles

Mass of the carbonate = 1.056 g

But;

Molar mass = Mass ÷ moles

                   = 1.056 g ÷ 0.00854 moles

                   = 123.65 g/mol

The molar mass of metal carbonate = 123.65 g/mol

Atomic mass of carbon = 16

Atomic mass of oxygen = 12.01

Therefore;

123.65 g = M + 12.01 + (16 ×3)

M = 63.64 g

The atomic mass of M is 63.64 approximately the same as that of copper.

Atomic mass of Cu is 63.546

Therefore, identity of M is Cu

explanation:

since this is put under health, i would define "ethical (medical) behavior" the way the oath for doctors is recited.   "first do no harm."

but the term in general means when given a choice between right and wrong, we should always choose right. if we do, then we are practicing ethical behavior.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.