Which of the reactions are spontaneous (favorable)? a. dhap↽−−⇀glyceraldehyde-3-phosphateδ =3.8 kj/mol b. c2h4+h2−→−−rh(i)c2h6δ=−150.97 kj/mol c. glutamate+nad++h2o⟶nh+4+α-ketogluta rate+nadh+h+δ=3.7 kcal/mol d. c6h13o9p+atp⟶c6h14o12p2+adpδ=−14.2 kj/mol e. l -malate+nad+⟶oxaloacetate+nadh+h+δ= 29.7 kj/mol

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the answer is 0.42 is that is an option. this question provides no info