Barium can be analyzed by precipitating it as baso4 and determining the mass of the precipitate. when a 0.269 g sample of a barium compound was treated with excess h2so4, 0.0891 g of baso4 formed. what percentage of barium is in the compound?

Percentage of Ba in the compound is 19.5%

Explanation:

According to formula of , 1 molecule of contains 1 molecule of Ba.

So, 1 mol of contains 1 mol of Ba.

Molar mass of = 233.38 g/mol

Number of moles of a compound is ratio of mass to molar mass of the compound.

So, 0.0891 g of = of = 0.000382 moles of

So, moles of Ba present in sample = 0.000382 moles

Molar mass of Ba = 137.33 g/mol

So, mass of Ba in sample =

So, % of Ba in sample = % = 19.5%

explanation:

i think option no d is the correct answer