Calculate the amount of energy in kilojoules needed to change 459 g of water ice at −10 ∘c to steam at 125 ∘c. the following constants may be useful: cm (ice)=36.57 j/(mol⋅∘c) cm (water)=75.40 j/(mol⋅∘c) cm (steam)=36.04 j/(mol⋅∘c) δhfus=+6.01 kj/mol δhvap=+40.67 kj/mol express your answer with the appropriate units. view available hint(s)

Explanation:-

The conversions involved in this process are :

Now we have to calculate the enthalpy change:

where,

= enthalpy change = ?

m = mass of water = 459 g

= specific heat of ice =

= specific heat of water =  

= specific heat of steam =

n = number of moles of water =

= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

= enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get:

(1kJ = 1000 J)

Therefore, the enthalpy change is

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your answer is c) plasma

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