If you want to prepare 0.50 liters of a 0.35 m solution of nano3, how many grams of the salt should
you weigh out?

14.87 g

We are given;

Volume as 0.5 liters

Molarity as 0.35 M

We are required to calculate the mass of the solute NaNO₃

Step 1 : Find the number of moles of the solute NaNO₃

Moles = Molarity × Volume

Moles = 0.35 M × 0.5 L

         = 0.175 moles

Step 2: Mass of the solute NaNO₃

Mass is calculated by multiplying the number of moles by the molar mass of the compound.

Molar mass of NaNO₃ = 84.9947 g/mol

Therefore;

Mass of NaNO₃ = 0.175 moles × 84.9947 g/mol

                          = 14.874 g

                         = 14.87 g

Thus, the mass of the salt solute is 14.87 g

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a. hope i'm right

explanation: