Using 25.0cm3 of aqueous lithium hydroxide, concentration 2.48mol/dm3, 2.20g of hydrated lithium sulfate was obtained. calculate the percentage yield, giving your answer to one decimal place.
2lioh h2so4 → li2so4 2h2o li2so4 h2o → li2so4.h2o
the number of moles of lioh used =
the number of moles of li2so4.h2o which could be formed =
mass of one mole of li2so4.h2o = 128 g
the maximum yield of li2so4.h2o =
percentage yield = % [4]

Percentage yield = 27.8 %

Explanation:

Given data:

Volume of lithium hydroxide = 25.0 cm³ (0.025 dm³)

Concentration of lithium hydroxide =M= 2.48 mol/dm³

Actual yield of hydrated lithium sulfate = 2.20 g

Percentage yield = ?

Solution:

Chemical equation:

2LiOH + H₂SO₄ → Li₂SO₄.2H₂O

Moles of lithium hydroxide:

Molarity =  moles/ volume of solution

2.48 mol/dm³ = moles / 0.025 dm³

moles = 2.48 mol/dm³ × 0.025 dm³

moles = 0.062 mol

Now we compare the moles of hydrated lithium sulfate with lithium hydroxide:

  LiOH         :    Li₂SO₄.2H₂O

      1            :        1

     0.062   :       0.062

Mass of Li₂SO₄.2H₂O:

Mass = moles × molar mass

Mass = 0.062 mol × 128 g/mol

Mass =  7.9 g

Percentage yield:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 2.20 g/ 7.9 g × 100

Percentage yield = 27.8 %

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.