Chemistry, 04.11.2019 05:31 wyattgrubb00

Arrange the following particles from smallest to largest.

f, f^-1, br, br^-1

Answers: 3

Show answers

Answers

Answer from: elisesnelson

F, F⁻¹, Br, Br⁻¹

Explanation:

Atomic radii:

It is the inter nuclear distance between bonded atom.

Trend along group:

When we move from top to bottom in a group atomic size increases with increase of atomic number because of addition of electron in next energy level. Thus nuclear attraction becomes weaker on valence electrons and size gets increased. Moreover shielding effect also protect the valance electrons from nuclear attraction.

when we move from bottom to top the atomic size decreases because of decrease in atomic number and energy level.

For example

In halogens the fluorine has smaller size than rest of halogens elements because it is present in top of this column. while bromine is present third to the fluorine that's why its atomic size is larger than fluorine. When an extra electron is added the atomic size becomes greater than neutral atom because of addition of electron to the next energy level. That's why anionic size is greater than neutral atom.

The given particles thus arranged in smallest to largest size in following order.

F, F⁻¹, Br, Br⁻¹

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

Yes she is correct. the answer is completely correct

Another question on Chemistry

Chemistry, 21.06.2019 23:30

Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isí‘ťí‘ť=í‘›í‘›í‘›í‘›í‘›í‘›í‘‰í‘‰more accurate estimates can be made with the van der waals equationí‘ťí‘ť=í‘›í‘›í‘›í‘›í‘›í‘›í‘‰í‘‰â’í‘›í‘›í‘źí‘źâ’í‘ží‘ží‘›í‘›2í‘‰í‘‰2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?

Answers: 1

Answer

Chemistry, 22.06.2019 12:10

|using the periodic tablewarm-upuse the periodic table in the tools bar to answer the following questions.what elemental classification does oxygen belongto? done

Answers: 3

Answer

Chemistry, 22.06.2019 17:00

In a heat engine of 1000 j of heat enters the system and the piston does 500 j of work what is the final internal energy of the system if the inital energy was 2000 j we have to do all of these down here 1)write the equation 2)list out your know variables 3)plug the numbers into the equations 4)solve 5)write your solution statemtn that includes inital energuy and final energuy added

Answers: 1

Answer

Chemistry, 23.06.2019 03:20

High-pressure liquid chromatography (hplc) is a method used in chemistry and biochemistry to purify chemical substances. the pressures used in this procedure range from around 500 kilopascals (500,000 pa) to about 60,000 kpa (60,000,000 pa). it is often convenient to know the pressure in torr. if an hplc procedure is running at a pressure of 1.03×108 pa , what is its running pressure in torr?

Answers: 3

Answer

You know the right answer?

Arrange the following particles from smallest to largest.

f, f^-1, br, br^-1...

Questions