The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. glucose-6-phosphate was mixed with the enzyme under standard conditions and the reaction was allowed to come to equilibrium. if the keq' is 0.50 and the equilibrium [glucose-6-phosphate] is 1.33 m, what is the equilibrium [fructose-6-phosphate]?

i think it is true since you can test the answer and can use observations to complete it.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

colorless gas, exhibiting a blue glow when placed in an electric field

b) solid

its a type of rock