Urea is a product of digestion of proteins and other foods that contain nitrogen. it can react with water and acid to form ammonium ions and bicarbonate ions according to the equation below: (upper n upper h subscript 2) subscript 2 upper c upper o (a q) plus 2 upper h subscript 2 upper o (l) plus upper h superscript plus (a q) right arrow 2 upper n upper h subscript 4 superscript plus (a q) plus upper h upper c upper o subscript 3 superscript minus (a q). the enzyme urease catalyzes this reaction. if urease is added to a solution that contains ammonia and other nitrogen-containing compounds (but no urea), will the urease catalyze any reactions? explain your answer.

The urease will not catalyze any reaction.

Explanation:

The hydrolysis reaction of urea is:

(NH₂)₂CO + 2 H₂O + H⁺ ⇒ 2 NH₄⁺ + HCO₃⁻

Urease is an enzyme that catalyzes the urea hydrolysis reaction. Enzymes are very specific referring to the substrates they catalyze. If the solution does not contain urea, the urease will not bind to any of the substances in the solution, so it will not catalyze any reaction in the solution.

Urease is an enzyme.

Enzymes are highly specific in the reactions they catalyze.

Enzymes can typically bind only to the substrate(s) for the reaction they catalyze.

If the solution contains no urea, urease will not bind to any of the substances in the solution, so it will not catalyze any reactions in the solution.

Explanation:

Those are the answers.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml