The generic metal hydroxide m(oh)2 has ksp = 3.25×10−12. (note: in this particular problem, because of the magnitude of the ksp and the stoichiometry of the compound, the contribution of oh− from water can be ignored. however, this may not always be the case.)

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

the answer is a for sure mark brainliest i had got this right on usatestprep