Abottle in lab is labeled [cocl2.6h2o] = 0.71 m in 9.217 m hcl. if you determine [cocl42-] to be 0.361 m at a particular temperature using absorbance measurements, what must be the value of [co(h2o)62+] in the solution at that temperature? express your response to three digits after the decimal.

[Co(H₂O)₆]²⁺ = 0.361 M

Explanation:

[CoCl₂ . 6H₂O] + 2Cl⁻ → [CoCl₄]²⁻ + 6H₂O

[Co(H₂O)₆]²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O

[CoCl₄]²⁻ = 0.361 M ∴ [Co(H₂O)₆]²⁺ = 0.361 M

The equation shows that the concentration of [Co(H₂O)₆]²⁺ should be equal to the concentration of [CoCl₄]²⁻.

the answer is na (sodium)

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.