Write a balanced chemical equation, the ionic equation, and net ionic equation for the following a.) sulfuric acid (aq) + sodium hydroxide (aq) -> b.) nacl(aq)+agno3(aq)->

Explanation:

Chemical equation:

H₂SO₄ (aq) + NaOH (aq)      →   Na₂SO₄(aq) + H₂O(l)

Balanced chemical equation:

H₂SO₄ (aq) + 2NaOH (aq)      →  Na₂SO₄(aq) + 2H₂O(l)

Ionic equation:

2Na⁺(aq)   + 2OH⁻(aq)   +   2H⁺(aq)  +  SO₄²⁻(aq)     →  2Na⁺(aq) + SO₄²⁻(aq) + 2H₂O(l)

Net ionic equation:

2OH⁻(aq)   +   2H⁺(aq)     →   2H₂O(l)

The SO₄²⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

2nd

Chemical equation:

NaCl(aq)     +    AgNO₃(aq)     →  NaNO₃(s) + AgCl(aq)

It is the double displacement reaction. The sodium chloride react with silver nitrate and form sodium nitrate and silver chloride.

Balanced chemical equation:

NaCl(aq)     +    AgNO₃(aq)     →  NaNO₃(s) + AgCl(aq)

Ionic equation:

Na⁺(aq)   + Cl⁻(aq)   +   Ag⁺(aq)  +  NO₃⁻(aq)     →  NaNO₃(s) + Ag⁺(aq)  + Cl⁻(aq)

Net ionic equation:

Na⁺(aq)  +  NO₃⁻(aq)     →  NaNO₃(s)

The  Cl⁻((aq) and Ag⁺(aq) are spectator ions that's why these are not written in net ionic equation. The sodium nitrate can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

1 is the answer to this problem