A1.0 l sample of gas is collected under a pressure of 912 torr and 0 degrees celcius what is the volume of the gas at standard temperature and pressure

Final volume = 1.2 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 1 L

Initial pressure = 912 torr (912/760 = 1.2 atm)

Initial temperature = 0°C (0 + 273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.2 atm × 1 L × 273 K / 273 K × 1 atm

V₂  =  327.6 atm .L.  K  / 273 K . atm

V₂  = 1.2 L