Let us assume that cr(oh)3(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented in the transition) would go to completion.
cr3+(aq)+3naoh(aq) → cr(oh)3(s)+3na+(aq)
if you had a 0.600 l solution containing 0.0130 m of cr3+(aq), and you wished to add enough 1.26 m naoh(aq) toprecipitate all of the metal, what is the minimum amount of the naoh(aq) solution you would need to add? assume that the naoh(aq) solution is the only source of oh−(aq) for the precipitation.
express the volume to three significant figures and include the appropriate units.

0.0295 liters is the minimum amount of the NaOH(aq) solution we would add.

Explanation:

Molarity of chromium ions ,M= 0.0130 M

Volume of chromium ions ,V= 0.600 L

Moles of chromium ions = n

According to reaction , 1 moles of chromium ions reacts with 3 moles of NaOH.

Then 0.0078 moles of chromium ions will react with :

of NaOH

Moles of NaOH = n' = 0.0234 moles

Molarity of NaOH solution = M'= 1.26 M

Volume of the NaOH solution = V' = ?

0.0295 liters is the minimum amount of the NaOH(aq) solution we would add.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )