Calculate the volume of 50 % (w/w) sodium hydroxide solution (its density ~ 1.52 g/ml) needed to prepare ~0.1 m naoh solution, using a 10-ml graduated cylinder.

0.05 mL

Explanation:

Initially, we have a concentrated solution of NaOH, to which we will add water to get a dilute one. To calculate the volume of the initial solution that we have to measure, we can use the dilution rule:

C₁ × V₁ = C₂ × V₂

where,

C₁ is the initial concentration (50% w/w; ρ = 1.52 g/mL)

V₁ is the initial volume

C₂ is the final concentration (0.1 M)

V₂ is the final volume (10 mL)

First, we have to calculate the weight/volume percentage and then the molarity of the first solution.

Now, we can apply the dilution rule.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml