Which is the correctly balanced chemical equation for the reaction of koh and h2so4?
koh →h,50, k*+502-
2koh+h,50. →k,50.
2koh+h, 50. →k,50 +2h,0
koh → h,50. →k, so. →h,0

i'm pretty sure it is letter c.) car

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied