What is the potential energy of a car with a mass of 1200kg at the top of a 42m high hill?

P.E = 493920 j

Explanation:

Given data:

Mass = 1200 kg

height = 42 m

Potential energy = ?

Solution:

Formula:

P.E = mgh

Now we will put the values in formula.

g = 9.8 m/s²

P.E = 1200 Kg × 9.8 m/s²× 42 m

P.E = 493920 Kg.m²/s²

Kg.m²/s² = j

P.E = 493920 j

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :