Hi plz answer, i stupid 4.35 l of n2, at 25 ∘c and 1.16 atm , is mixed with 2.20 l of o2, at 25 ∘c and 0.277 atm , and the mixture allowed to react. n2(g)+o2(g)→2no(g)

how much no, in grams, is produced?

Mass = 1.5 g

Explanation:

Given data:

Volume of N₂ = 4.35 L

Temperature = 25°C(25+273 = 298)

Pressure = 1.16 atm

Volume of O₂ = 2.20 L

Temperature = 25°C (25+273 = 298)

Pressure = 0.277 atm

Mass of NO produced = ?

Solution:

Chemical equation:

N₂ + O₂ → 2NO

Number of moles of N₂:

PV = nRT

n = PV/RT

n = 1.16 atm × 4.35 L / 0.0821 atm. L.K⁻¹. mol⁻¹×298 K

n = 5.046 atm. L/ 24.5  atm. L. mol⁻¹

n = 0.206 mol

Number of moles of O₂:

PV = nRT

n = PV/RT

n = 0.277 atm × 2.20 L / 0.0821 atm. L.K⁻¹. mol⁻¹×298 K

n = 0.609 atm. L/ 24.5  atm. L. mol⁻¹

n = 0.025 mol

Now we will compare the moles of NO with oxygen and nitrogen.

              O₂         :       NO

                1          :         2

               0.025  :    2×0.025=0.05 mol

                N₂       :       NO

                 1         :        2

                0.206 :      2×0.206=0.412 moL

Number of moles of NO produced by oxygen are less so it will limiting reactant.

Mass of NO:

Number of moles = mass/molar mass

Mass = Number of moles × molar mass

Mass = 0.05 mol × 30 g/mol

Mass = 1.5 g

c is the answer because when something is left after something evaporates that shows the chemical change.

no but i do not usually comment or use my voice that much when it comes to social media