The natural gas in a 30-l ngv fuel tank has a pressure of 2.05* 10^4 kpa at a temperature of 297 k. how many kilograms of fuel are in the tank

4727.2  × 10³ Kg

Explanation:

Given data:

Pressure of gas = 2.05 ×10⁴ KPa (202.32 atm)

Temperature = 297 K

Volume = 30 L

Mass of fuel = ?

Solution:

Molar mass of gas is missing. It is 19 g/mol.

Formula:

PV = nRT

n = PV/RT

n = 202.32 atm × 30 L / 0.0821 atm. L. mol⁻¹.k⁻¹ × 297 K

n = 6069.6 atm.L / 24.4  atm. L. mol⁻¹

n = 248.8 mol

Mass:

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 248.8 mol × 19 g/mol

Mass = 4727.2 g

In kilogram:

4727.2 g /1 g × 1000 Kg

4727.2  × 10³ Kg

it's c. elements are placed in rows based on how may valencies electrons have.