An ice cube of mass 9.0 g at temperature 0∘c is added to a cup of coffee, whose temperature is 90 ∘c and which contains 110 g of liquid. assume the specific heat capacity of the coffee is the same as that of water. the heat of fusion of ice (the heat associated with ice melting) is 6.0 kj/mol.

Answer : The temperature of the coffee after the ice melts is

Explanation :

In this question we have to determine the temperature of the coffee after the ice melts.

Heat lost by coffee = Heat gained by ice

where,

= specific heat of coffee = specific heat of water =  (as per question)

= specific heat of ice =

= mass of coffee = 110 g

= mass of ice = 9.0 g

= final temperature = ?

= initial temperature of coffee =

= initial temperature of ice =

n = number of moles of ice =

= 6.0 kJ/mol = 6000 J/mol

Now put all the given values in the above formula, we get

Therefore, the temperature of the coffee after the ice melts is

3 1/4 %

explanation:

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