It has been determined that the body can generate 5500 kj of energy during one hour of strenuous exercise. perspiration is the body’s mechanism for eliminating this heat. what mass of water would have to be evaporated through perspiration to rid the body of the heat generated during 2 hours of exercise

There is 4.88 kg of water evaporated.

Explanation:

Step 1: Data given

5500 kJ of energy during one hour of strenuous exercise.

Δh = Heat of vaporization of water is 40.6 kJ/mol

Step 2: Calculate the mass of water evaporated

Q = 2* 5500 kJ = 11000 kJ

mass =  [( Q ) / ( Δh ) ] [ Molar mass of water]

mass  = [ ( 11,000 kj /  40.6  kJ/mol) * 18.02 g/mol )

mass = 4882.27 grams ≈ 4.88 kg of water

There is 4.88 kg of water evaporated.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.